数列{an}满足an+1+an=4n-3(n∈N*).若{an}是等差数列,求其通项公式
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数列{an}满足an+1+an=4n-3(n∈N*).若{an}是等差数列,求其通项公式
数列{an}满足an+1+an=4n-3(n∈N*).若{an}是等差数列,求其通项公式
数列{an}满足an+1+an=4n-3(n∈N*).若{an}是等差数列,求其通项公式
An+An+1=4n-3,n代入n-1得到,An-1+An=4n-7
两个式子相减 2d=An+1-An-1=4,d=2 公差为2
那么知道,An+1=An+2代入,2*An+2=4n-3
An=2n-2.5
不懂的欢迎追问,
用Sn-(Sn-1)=an算
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