下面那道怎么化简.
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下面那道怎么化简.
下面那道怎么化简.
下面那道怎么化简.
原式 = [1/(x+1) + 1/(x-1)] ÷ 1/(x+1)(x-1)
= 2x / [(x+1)(x-1)] *(x+1)(x-1)
= 2x
= 1