设M是平行四边形ABCD的对角线的交点.证明对任意一点O,向量OM=(向量OA+向量OB+向量OC+向量OD)四分之一还有一题:设AD,BE,CF是三角形ABC的三条中线,用向量AB和AC表示向量AD,BE,CF,并且求向量AD+BE+CF
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![设M是平行四边形ABCD的对角线的交点.证明对任意一点O,向量OM=(向量OA+向量OB+向量OC+向量OD)四分之一还有一题:设AD,BE,CF是三角形ABC的三条中线,用向量AB和AC表示向量AD,BE,CF,并且求向量AD+BE+CF](/uploads/image/z/5473725-69-5.jpg?t=%E8%AE%BEM%E6%98%AF%E5%B9%B3%E8%A1%8C%E5%9B%9B%E8%BE%B9%E5%BD%A2ABCD%E7%9A%84%E5%AF%B9%E8%A7%92%E7%BA%BF%E7%9A%84%E4%BA%A4%E7%82%B9.%E8%AF%81%E6%98%8E%E5%AF%B9%E4%BB%BB%E6%84%8F%E4%B8%80%E7%82%B9O%2C%E5%90%91%E9%87%8FOM%3D%EF%BC%88%E5%90%91%E9%87%8FOA%2B%E5%90%91%E9%87%8FOB%2B%E5%90%91%E9%87%8FOC%2B%E5%90%91%E9%87%8FOD%29%E5%9B%9B%E5%88%86%E4%B9%8B%E4%B8%80%E8%BF%98%E6%9C%89%E4%B8%80%E9%A2%98%EF%BC%9A%E8%AE%BEAD%2CBE%2CCF%E6%98%AF%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E7%9A%84%E4%B8%89%E6%9D%A1%E4%B8%AD%E7%BA%BF%2C%E7%94%A8%E5%90%91%E9%87%8FAB%E5%92%8CAC%E8%A1%A8%E7%A4%BA%E5%90%91%E9%87%8FAD%2CBE%2CCF%2C%E5%B9%B6%E4%B8%94%E6%B1%82%E5%90%91%E9%87%8FAD%2BBE%2BCF)
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