在△ABC中,内角A,B,C所对的边长分别是a,b,c(1):若c=2,C=π/3,且△ABC的面积为 根号3 ,求a,b的值(2):若sinC+sin(B-A)=sin2A,试判断△ABC的形状
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![在△ABC中,内角A,B,C所对的边长分别是a,b,c(1):若c=2,C=π/3,且△ABC的面积为 根号3 ,求a,b的值(2):若sinC+sin(B-A)=sin2A,试判断△ABC的形状](/uploads/image/z/5487683-59-3.jpg?t=%E5%9C%A8%E2%96%B3ABC%E4%B8%AD%2C%E5%86%85%E8%A7%92A%2CB%2CC%E6%89%80%E5%AF%B9%E7%9A%84%E8%BE%B9%E9%95%BF%E5%88%86%E5%88%AB%E6%98%AFa%2Cb%2Cc%EF%BC%881%EF%BC%89%EF%BC%9A%E8%8B%A5c%3D2%2CC%3D%CF%80%2F3%2C%E4%B8%94%E2%96%B3ABC%E7%9A%84%E9%9D%A2%E7%A7%AF%E4%B8%BA+%E6%A0%B9%E5%8F%B73+%2C%E6%B1%82a%2Cb%E7%9A%84%E5%80%BC%EF%BC%882%EF%BC%89%EF%BC%9A%E8%8B%A5sinC%2Bsin%EF%BC%88B-A%EF%BC%89%3Dsin2A%2C%E8%AF%95%E5%88%A4%E6%96%AD%E2%96%B3ABC%E7%9A%84%E5%BD%A2%E7%8A%B6)
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