计算1/1X3+1/2X4+1/3X5+.+1/10X12

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计算1/1X3+1/2X4+1/3X5+.+1/10X12
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计算1/1X3+1/2X4+1/3X5+.+1/10X12
计算1/1X3+1/2X4+1/3X5+.+1/10X12

计算1/1X3+1/2X4+1/3X5+.+1/10X12
裂项求和咯
把每一项拆开.1/(N*(N+2))=1/2*(1/N+1/(N+2))
原式=(1/2)X((1-1/3)+(1/2-1/4)+(1/3-1/5)+.+(1/10-1/12))
消去后=(1/2)X(1+1/2-1/11-1/12)=115/132

太难了

楼主啊,这个问题很累,你到底是说1/[n*(n+2)],还是说1/n*(n+2)?
用极限运算去算吧,书上都有公式。不是很复杂,下次你整个 1/100*102 ,再来。

175/132
1/1X3+1/2X4+1/3X5+......+1/10X12 =
1/2(1-1/3) + 1/2(1/2-1/4) + 1/2(1/3 - 1/5) +.....+1/2(1/10-1/12)
=1/2(1+1/2-1/11-1/12) = 175/132

175/264
1/2(1-1/3+1/2-1/4+1/3-1/5+......+1/10-1/12)==1/2(1+1/2-1/11-1/12)=175/264
其实:是1/2{(n+2)-n}/n(n+2)通项的和