作业帮若tana+1/tana=10/3,a属于（π/4,π/2）,则sin(2a+π/2)的值为A-根号2/10 B根号2/10 C5根号2/10 D7根号2/10你答案算错了应该选D
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若tana+1/tana=10/3,a属于（π/4,π/2）,则sin(2a+π/2)的值为A-根号2/10 B根号2/10 C5根号2/10 D7根号2/10你答案算错了应该选D
若tana+1/tana=10/3,a属于（π/4,π/2）,则sin(2a+π/2)的值为
A-根号2/10 B根号2/10 C5根号2/10 D7根号2/10
你答案算错了应该选D
若tana+1/tana=10/3,a属于（π/4,π/2）,则sin(2a+π/2)的值为A-根号2/10 B根号2/10 C5根号2/10 D7根号2/10你答案算错了应该选D
tana+1/tana=sina/cosa+cosa/sina=[(sina)^2+(cosa)^2]/sinacosa=1/[1/2*2sinacos]
=2/sin2a=10/3
sin2a=3/5
π/4
所以cos2a<0
因为(sin2a)^2+(cos2a)^2=1
所以cos2a=-4/5
sin(2a+π/2)=cos2a=-4/5
已知3π/4小于a小于π,tana+1/tana=-10/3,求tana,
已知3π/4＜a＜π ,tana+1/tana=-10/3 则tana=
tan²a-2tana-3=0.tana=3或tana=-1
1+tanA/1-tanA=3+2.828 tanA=
1+tana/1-tana=-3
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tanA=-1,A=?
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