如图所示,在三角形ABC中,AD是∠BAC的角平分线,E,F分别为AB,AC上的点,且∠EDF+∠EAF=180°.求证:DE=DF
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![如图所示,在三角形ABC中,AD是∠BAC的角平分线,E,F分别为AB,AC上的点,且∠EDF+∠EAF=180°.求证:DE=DF](/uploads/image/z/5520690-18-0.jpg?t=%E5%A6%82%E5%9B%BE%E6%89%80%E7%A4%BA%2C%E5%9C%A8%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E4%B8%AD%2CAD%E6%98%AF%E2%88%A0BAC%E7%9A%84%E8%A7%92%E5%B9%B3%E5%88%86%E7%BA%BF%2CE%2CF%E5%88%86%E5%88%AB%E4%B8%BAAB%2CAC%E4%B8%8A%E7%9A%84%E7%82%B9%2C%E4%B8%94%E2%88%A0EDF%2B%E2%88%A0EAF%3D180%C2%B0.%E6%B1%82%E8%AF%81%3ADE%3DDF)
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