(sin(180°+2x))/(1+cos2x)*(cos2x0/(cos(90°+x))=
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(sin(180°+2x))/(1+cos2x)*(cos2x0/(cos(90°+x))=
(sin(180°+2x))/(1+cos2x)*(cos2x0/(cos(90°+x))=
(sin(180°+2x))/(1+cos2x)*(cos2x0/(cos(90°+x))=
(sin(180°+2x))/(1+cos2x)*(cos2x0/(cos(90°+2x))
=[-sin2x/(1+cos2x)][cos2x/(-sinx)]
=(sin2xcos2x)/(sinx(1+cos2x))
=(sin2xcos2x)/[2snxcos²x]
=(sin2xcos2x)/sin2xcosx
=cos2x/cosx
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