求sin(π/2+2x)=2sin(π/4+x)cos(π/4+x)的化简过程

已知-π/2＜x＜0,sin x+cos x=1/5求sin 2x+2 sin 已知sin(x+π/6)=1/3,求sin(5π/6-x)+sin^2(π/3-x) 已知sin(x+π/6)=1/4,求sin(5π/6-x)+sin^2(π/3-x) 2sin(x+π/4)sin(x-π/4)=? 求f【x】=2sin[x+π/4]sin[x-π/4]+sin2x的最大值 已知tan=2,求(cos x+sin x)/(cos x-sin x)+sin^2x 求sin^2(2x+π/3)的导数这样写为什么不对：[sin^2(2x+π/3)]'=[sin(2x+π/3)·sin(2x+π/3)]'=2[sin(2x+π/3)]'·sin(2x+π/3)=2cos(2x+π/3)·sin(2x+π/3)=sin(4x+2π/3) 求X解集：sinx=2sin(π/3-x) 已知F(X)=根号3COS^2 X+SIN XCOS X-2SIN X*SIN(X-π/6),求F(X)的最大值 求y=sin[sin(x^2)]的导数 2sin π/6 =sin π/3,吗,求解释,还有-sin π/6=sin- π/6吗 sin(π-α)=-2sin(π/2+α),求sinα·cosα 若tan(x-π)=2,求2sin^2x+1/cos^2x-sin^2x的值若tan(x-π)=2,求2sin^2x+1/cos^2x-sin^2x的值 求函数f(x)=2sin(π-x)sin(π/2-x)+2根号3sin^2x-根号3的单调递减区间 求证:(sin 2x /(1-cos 2x) )·(sin x /(1+sin x))=tan (π/4-x/2). sin^2(π/3-x)+sin^2(π/6+x) sin平方x-sinxcosx-2cos平方x 求sin(x-π/3)X为锐角 sin平方x-sinxcosx-2cos平方x=0 求sin(x-π/3) tanx/2=1/2,求sin(x+π/6)