f'(x)=3ax^2-8ax+4a=3a(x-2/3)(x-2) 告诉我是怎么算出的3a(x-2/3)(x-2) 怎么分解因式的
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/17 02:42:25
![f'(x)=3ax^2-8ax+4a=3a(x-2/3)(x-2) 告诉我是怎么算出的3a(x-2/3)(x-2) 怎么分解因式的](/uploads/image/z/5534407-55-7.jpg?t=f%27%28x%29%3D3ax%5E2-8ax%2B4a%3D3a%28x-2%2F3%29%28x-2%29+%E5%91%8A%E8%AF%89%E6%88%91%E6%98%AF%E6%80%8E%E4%B9%88%E7%AE%97%E5%87%BA%E7%9A%843a%28x-2%2F3%29%28x-2%29+%E6%80%8E%E4%B9%88%E5%88%86%E8%A7%A3%E5%9B%A0%E5%BC%8F%E7%9A%84)
x)KSרд5N3ҵH6Ir4*t5AӉ]/w>lg
}Ovv<_7iZTBdvXO$;z| O( $aBFF6yvPۀ9@0l &jWYZ E5@ EABjV*ĉP55յɘL
f'(x)=3ax^2-8ax+4a=3a(x-2/3)(x-2) 告诉我是怎么算出的3a(x-2/3)(x-2) 怎么分解因式的
f'(x)=3ax^2-8ax+4a=3a(x-2/3)(x-2) 告诉我是怎么算出的3a(x-2/3)(x-2) 怎么分解因式的
f'(x)=3ax^2-8ax+4a=3a(x-2/3)(x-2) 告诉我是怎么算出的3a(x-2/3)(x-2) 怎么分解因式的
3ax^2-8ax+4a=3a(x^2-(8/3)x+4/3)=3a(x^2-2x-(2/3)x+4/3)=3a(x-(2/3))(x-2)
解
3ax^2-8ax+4a
=a(3x²-8x+4)
=a(3x-2)(x-2)
=3a(3x/3-2/3)(x-2)
=3a(x-2/3)(x-2)
3ax^2-8ax+4a
=a(3x^2-8x+4)
1 -2
3 -2 =-2-6=-8
=a(x-2)(3x-2)
=3a(x-2/3)(x-2)
已知a>0,函数f(x)=2ax^6-ax^4+3ax^2,g(x)=ax^6+2ax^4-a比较f(x)与g(x)大小 用导数的方法
f(x)=ax²-ax-4
已知二次函数f(x)=ax^2-(2+4a)x+3a(a
f(x)=ax^2+2ax+1在[-3,2]上有最大值4 则实数a=
函数f(x)=ax^3+2ax+3a-4在区间(-1,1)上有零点,
已知函数f(x)=x^3+2ax^2+1/ax(a>0),则f(2)最小值
(ax^2-2ax-3a)÷(x-3)=
函数f(x)=x2-2ax+4a(x
函数f(x)=ax^3-x (a
已知函数f(x)=ax^2+4ax-4,若对于x∈【-3,-1】,f(x)
合并同类项5ax-4a^2-8ax^2+3ax-ax^2-4a^2x^25ax-4a^2-8ax^2+3ax-ax^2-4a^2x^2
导函数f(x)=ax^3-ax^2+[f‘(1)/2-1]已知f(x)=ax^3-ax^2+[f‘(1)/2-1]求用a标示 f‘(1),应该是f(x)=ax^3-ax^2+[f‘(1)/2-1]x
设函数f(x)=-x^2+4ax-3a^2,若0
设函数f(x)=-x^2+4ax-3a^2,若0
f(x)=2ax²+4(a-3)x+5的对称轴怎么算
设函数f(x)=-x^2+4ax-3a^2.若0
设函数f(x)=ax^3-(ax)^2-ax-a在x=1处取得极大值-2,a=
已知f(x)=1/3ax^3-x^2+ax+1在R上单增,求a的取值