周期数列的问题在数列{an} 中,已知 a1 = Lg3 ,a(n+2)-a(n+1)+an = 0求a2017 ..由题意知:a(n+2)=a(n+1)-an 所以:a(n+3)=a(n+2)-a(n+1)两式相加,可得:a(n+3)=-an问题就在这步,为什么不直接换成 an=-a(n+3) 然后根据a2017=a67
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![周期数列的问题在数列{an} 中,已知 a1 = Lg3 ,a(n+2)-a(n+1)+an = 0求a2017 ..由题意知:a(n+2)=a(n+1)-an 所以:a(n+3)=a(n+2)-a(n+1)两式相加,可得:a(n+3)=-an问题就在这步,为什么不直接换成 an=-a(n+3) 然后根据a2017=a67](/uploads/image/z/5556414-30-4.jpg?t=%E5%91%A8%E6%9C%9F%E6%95%B0%E5%88%97%E7%9A%84%E9%97%AE%E9%A2%98%E5%9C%A8%E6%95%B0%E5%88%97%7Ban%7D+%E4%B8%AD%2C%E5%B7%B2%E7%9F%A5+a1+%3D+Lg3+%2Ca%28n%2B2%29-a%28n%2B1%29%2Ban+%3D+0%E6%B1%82a2017+..%E7%94%B1%E9%A2%98%E6%84%8F%E7%9F%A5%3Aa%28n%2B2%29%3Da%28n%2B1%29-an+%E6%89%80%E4%BB%A5%3Aa%28n%2B3%29%3Da%28n%2B2%29-a%28n%2B1%29%E4%B8%A4%E5%BC%8F%E7%9B%B8%E5%8A%A0%2C%E5%8F%AF%E5%BE%97%3Aa%28n%2B3%29%3D-an%E9%97%AE%E9%A2%98%E5%B0%B1%E5%9C%A8%E8%BF%99%E6%AD%A5%2C%E4%B8%BA%E4%BB%80%E4%B9%88%E4%B8%8D%E7%9B%B4%E6%8E%A5%E6%8D%A2%E6%88%90+an%3D-a%28n%2B3%29+%E7%84%B6%E5%90%8E%E6%A0%B9%E6%8D%AEa2017%3Da67)
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