已知反比例函数y1=k1/x(k1>0)与一次函数y2=k2x+1(K2≠0)交于AB两点,AC⊥x轴于点C,若三角形OAC的面积为1,且AC:OC=2:1.(1)求一次函数和反比例函数的解析式
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![已知反比例函数y1=k1/x(k1>0)与一次函数y2=k2x+1(K2≠0)交于AB两点,AC⊥x轴于点C,若三角形OAC的面积为1,且AC:OC=2:1.(1)求一次函数和反比例函数的解析式](/uploads/image/z/5558703-15-3.jpg?t=%E5%B7%B2%E7%9F%A5%E5%8F%8D%E6%AF%94%E4%BE%8B%E5%87%BD%E6%95%B0y1%3Dk1%2Fx%28k1%EF%BC%9E0%29%E4%B8%8E%E4%B8%80%E6%AC%A1%E5%87%BD%E6%95%B0y2%3Dk2x%2B1%EF%BC%88K2%E2%89%A00%EF%BC%89%E4%BA%A4%E4%BA%8EAB%E4%B8%A4%E7%82%B9%2CAC%E2%8A%A5x%E8%BD%B4%E4%BA%8E%E7%82%B9C%2C%E8%8B%A5%E4%B8%89%E8%A7%92%E5%BD%A2OAC%E7%9A%84%E9%9D%A2%E7%A7%AF%E4%B8%BA1%2C%E4%B8%94AC%3AOC%3D2%EF%BC%9A1.%EF%BC%881%EF%BC%89%E6%B1%82%E4%B8%80%E6%AC%A1%E5%87%BD%E6%95%B0%E5%92%8C%E5%8F%8D%E6%AF%94%E4%BE%8B%E5%87%BD%E6%95%B0%E7%9A%84%E8%A7%A3%E6%9E%90%E5%BC%8F)
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