作业帮化简此题
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化简此题
化简此题
化简此题
原式=cos2α/[2cot(π/4+α)sin(^2)(π/4+α)]
=cos2α/[2cos(π/4+α)sin(π/4+α)]
=cos2α/sin(π/2+2α)
=cos2α/cos(2α)=1
原式=cos2α/[2cot(π/4+α)sin(^2)(π/4+α)]
=cos2α/[2cos(π/4+α)sin(π/4+α)]
=cos2α/sin(π/2+2α)
=cos2α/cos(2α)=1