作业帮x[500-10(x-120)]=12000 解方程
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x[500-10(x-120)]=12000 解方程
x[500-10(x-120)]=12000 解方程
x[500-10(x-120)]=12000 解方程
解由x[500-10(x-120)]=12000
得x[500-10x+1200]=12000
即x(1700-10x)=12000
即x(170-x)=1200
即-x^2+170x=1200
即x^2-170x+1200=0
且Δ=(-170)^2-4*1200=24100
故解得
x=（170+√24100)/2或x=（170-√24100)/2
即x=85+5√241或x=85-5√241
(x+60)x(1+10%)-(1-20%)x=120
x(120+x)*80％=x-76
x(x+1)(x-1)=120
x-x/4-120=x/2
0.5X+120+0.3X=X
x/（120-x）=x/60
x/(120-x)=(60-x)/60
25%X+三分之一X+120=X
536-120%x-x=x-80
(0.2-x)(500-100x)=120
3X+6×(10-X)=120
100-2x+5x=120(x+3)×5-2x=30100-(4x+1)-(4x+1)=204x+8=6x-10
100-2x+5x=120(x+3)×5-2x=30100-(4x+1)-(4x+1)=204x+8=6x-10
x[500-10(x-120)]=12000 解方程
[（500+x)/10]乘以(0.3-x)=120
x-(20%x+55%x)=120 X是什么
(168+X)/(288+X)=(120-X)/X怎么解
x-20%x=120,