e^lnx^2=?

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e^lnx^2=?
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e^lnx^2=?
e^lnx^2=?

e^lnx^2=?
令a=e^lnx²
两边取ln
lna=lne^lnx²
lna=lnx²*lne
lna=lnx²
所以原式=a=x²

(a-b)²+3(a-b)+2
令x=a-b
则=x²+3x+2
=x²+2x+x+2
=x(x+2)+(x+2)
=(x+1)(x+2)
=(a-b+1)(a-b+2)
a属于(π,3π/2)
所以tana>0
1/sin2a=-13/5
(sin²a+cos²a...

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(a-b)²+3(a-b)+2
令x=a-b
则=x²+3x+2
=x²+2x+x+2
=x(x+2)+(x+2)
=(x+1)(x+2)
=(a-b+1)(a-b+2)
a属于(π,3π/2)
所以tana>0
1/sin2a=-13/5
(sin²a+cos²a)/2sinacosa=-13/5
sin²a/sinacosa+cos²a/sinacosa=-26/5
sina/cosa+cosa/sina=-26/5
tana+1/tana=-26/5
所以5tan²a+26tana+5=0
tana=-1/5,tana=-5
而a属于(π,3π/2)
则tana>0
所以无解

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