解下列方程组(1){x+y-z=0,x-3y+2z=1,3x+2y-z=4

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/26 16:48:38
解下列方程组(1){x+y-z=0,x-3y+2z=1,3x+2y-z=4
x){|O;?[4 5++ul t*t+l u+@b&6IEd/!6P-SaW0nP[ Ro5ԅf4*e cVؚ:^ LW45slA$ف< ;y

解下列方程组(1){x+y-z=0,x-3y+2z=1,3x+2y-z=4
解下列方程组(1){x+y-z=0,x-3y+2z=1,3x+2y-z=4

解下列方程组(1){x+y-z=0,x-3y+2z=1,3x+2y-z=4
x+y-z=0 (1)
x-3y+2z=1 (2)
3x+2y-z=4 (3)
(1)×2+(2)
3x-y=1 (4)
(3)-(1)
2x+y=4 (5)
(4)+(5)
5x=5
所以
x=1
y=3x-1=2
z=x+y=3