操作:如图①,△ABC是正三角形,△BDC是顶角∠BDC=120°的等腰三角形,以D为顶点作一个60°角,角的两边分别交AB、AC边于M、N两点,连接MN.探究:线段BM、MN、NC之间的关系,并加以说明.说明:⑴如
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![操作:如图①,△ABC是正三角形,△BDC是顶角∠BDC=120°的等腰三角形,以D为顶点作一个60°角,角的两边分别交AB、AC边于M、N两点,连接MN.探究:线段BM、MN、NC之间的关系,并加以说明.说明:⑴如](/uploads/image/z/584359-7-9.jpg?t=%E6%93%8D%E4%BD%9C%EF%BC%9A%E5%A6%82%E5%9B%BE%E2%91%A0%2C%E2%96%B3ABC%E6%98%AF%E6%AD%A3%E4%B8%89%E8%A7%92%E5%BD%A2%2C%E2%96%B3BDC%E6%98%AF%E9%A1%B6%E8%A7%92%E2%88%A0BDC%EF%BC%9D120%C2%B0%E7%9A%84%E7%AD%89%E8%85%B0%E4%B8%89%E8%A7%92%E5%BD%A2%2C%E4%BB%A5D%E4%B8%BA%E9%A1%B6%E7%82%B9%E4%BD%9C%E4%B8%80%E4%B8%AA60%C2%B0%E8%A7%92%2C%E8%A7%92%E7%9A%84%E4%B8%A4%E8%BE%B9%E5%88%86%E5%88%AB%E4%BA%A4AB%E3%80%81AC%E8%BE%B9%E4%BA%8EM%E3%80%81N%E4%B8%A4%E7%82%B9%2C%E8%BF%9E%E6%8E%A5MN.%E6%8E%A2%E7%A9%B6%EF%BC%9A%E7%BA%BF%E6%AE%B5BM%E3%80%81MN%E3%80%81NC%E4%B9%8B%E9%97%B4%E7%9A%84%E5%85%B3%E7%B3%BB%2C%E5%B9%B6%E5%8A%A0%E4%BB%A5%E8%AF%B4%E6%98%8E.%E8%AF%B4%E6%98%8E%EF%BC%9A%E2%91%B4%E5%A6%82)
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