设函数f(x)的图像关于点(1,3/2)对称,且存在反函数f-1(x),若f(3)=0,则f-1(3)等于设函数f(x)的图像关于点(1,3/2)对称,且存在反函数f-1(x),若f(3)=0,则f-1(3)等于A .-1 B .1 C .-2 D .2怎么得到x1+x2=2;y
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![设函数f(x)的图像关于点(1,3/2)对称,且存在反函数f-1(x),若f(3)=0,则f-1(3)等于设函数f(x)的图像关于点(1,3/2)对称,且存在反函数f-1(x),若f(3)=0,则f-1(3)等于A .-1 B .1 C .-2 D .2怎么得到x1+x2=2;y](/uploads/image/z/592541-53-1.jpg?t=%E8%AE%BE%E5%87%BD%E6%95%B0f%EF%BC%88x%EF%BC%89%E7%9A%84%E5%9B%BE%E5%83%8F%E5%85%B3%E4%BA%8E%E7%82%B9%EF%BC%881%2C3%2F2%EF%BC%89%E5%AF%B9%E7%A7%B0%2C%E4%B8%94%E5%AD%98%E5%9C%A8%E5%8F%8D%E5%87%BD%E6%95%B0f-1%28x%29%2C%E8%8B%A5f%283%29%3D0%2C%E5%88%99f-1%283%29%E7%AD%89%E4%BA%8E%E8%AE%BE%E5%87%BD%E6%95%B0f%EF%BC%88x%EF%BC%89%E7%9A%84%E5%9B%BE%E5%83%8F%E5%85%B3%E4%BA%8E%E7%82%B9%EF%BC%881%2C3%2F2%EF%BC%89%E5%AF%B9%E7%A7%B0%2C%E4%B8%94%E5%AD%98%E5%9C%A8%E5%8F%8D%E5%87%BD%E6%95%B0f-1%28x%29%2C%E8%8B%A5f%283%29%3D0%2C%E5%88%99f-1%283%29%E7%AD%89%E4%BA%8EA+.-1+B+.1+C+.-2+D+.2%E6%80%8E%E4%B9%88%E5%BE%97%E5%88%B0x1%2Bx2%3D2%EF%BC%9By)
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