请问一下,如果y=4x*x*x+3x*x+x+2x+1,怎么用MATLAB实现,x等于多少y谢谢各位了!我只有这么点分数,拜托大家了
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![请问一下,如果y=4x*x*x+3x*x+x+2x+1,怎么用MATLAB实现,x等于多少y谢谢各位了!我只有这么点分数,拜托大家了](/uploads/image/z/596871-63-1.jpg?t=%E8%AF%B7%E9%97%AE%E4%B8%80%E4%B8%8B%2C%E5%A6%82%E6%9E%9Cy%3D4x%2Ax%2Ax%2B3x%2Ax%2Bx%2B2x%2B1%2C%E6%80%8E%E4%B9%88%E7%94%A8MATLAB%E5%AE%9E%E7%8E%B0%2Cx%E7%AD%89%E4%BA%8E%E5%A4%9A%E5%B0%91y%E8%B0%A2%E8%B0%A2%E5%90%84%E4%BD%8D%E4%BA%86%21%E6%88%91%E5%8F%AA%E6%9C%89%E8%BF%99%E4%B9%88%E7%82%B9%E5%88%86%E6%95%B0%2C%E6%8B%9C%E6%89%98%E5%A4%A7%E5%AE%B6%E4%BA%86)
请问一下,如果y=4x*x*x+3x*x+x+2x+1,怎么用MATLAB实现,x等于多少y谢谢各位了!我只有这么点分数,拜托大家了
请问一下,如果y=4x*x*x+3x*x+x+2x+1,怎么用MATLAB实现,x等于多少y
谢谢各位了!
我只有这么点分数,拜托大家了
请问一下,如果y=4x*x*x+3x*x+x+2x+1,怎么用MATLAB实现,x等于多少y谢谢各位了!我只有这么点分数,拜托大家了
>> x=solve('y=4*x*x*x+3*x*x+x+2*x+1','x')
x =
1/4*(-3+8*y+2*(9-12*y+16*y^2)^(1/2))^(1/3)-3/4/(-3+8*y+2*(9-12*y+16*y^2)^(1/2))^(1/3)-1/4
-1/8*(-3+8*y+2*(9-12*y+16*y^2)^(1/2))^(1/3)+3/8/(-3+8*y+2*(9-12*y+16*y^2)^(1/2))^(1/3)-1/4+1/2*i*3^(1/2)*(1/4*(-3+8*y+2*(9-12*y+16*y^2)^(1/2))^(1/3)+3/4/(-3+8*y+2*(9-12*y+16*y^2)^(1/2))^(1/3))
-1/8*(-3+8*y+2*(9-12*y+16*y^2)^(1/2))^(1/3)+3/8/(-3+8*y+2*(9-12*y+16*y^2)^(1/2))^(1/3)-1/4-1/2*i*3^(1/2)*(1/4*(-3+8*y+2*(9-12*y+16*y^2)^(1/2))^(1/3)+3/4/(-3+8*y+2*(9-12*y+16*y^2)^(1/2))^(1/3))
即
x1=1/4*(-3+8*y+2*(9-12*y+16*y^2)^(1/2))^(1/3)-3/4/(-3+8*y+2*(9-12*y+16*y^2)^(1/2))^(1/3)-1/4
x2= -1/8*(-3+8*y+2*(9-12*y+16*y^2)^(1/2))^(1/3)+3/8/(-3+8*y+2*(9-12*y+16*y^2)^(1/2))^(1/3)-1/4+1/2*i*3^(1/2)*(1/4*(-3+8*y+2*(9-12*y+16*y^2)^(1/2))^(1/3)+3/4/(-3+8*y+2*(9-12*y+16*y^2)^(1/2))^(1/3))
x3= -1/8*(-3+8*y+2*(9-12*y+16*y^2)^(1/2))^(1/3)+3/8/(-3+8*y+2*(9-12*y+16*y^2)^(1/2))^(1/3)-1/4-1/2*i*3^(1/2)*(1/4*(-3+8*y+2*(9-12*y+16*y^2)^(1/2))^(1/3)+3/4/(-3+8*y+2*(9-12*y+16*y^2)^(1/2))^(1/3))