1)已知分式3/(x^2+3x+1)=3/8,求1/(2x^2+6x-3)的值.2)已知x^2-5x-2009=0,求[(x-2)^3-(x-1)^2+1]/x-2的值.3)(2a-b-c)/[(a-b)(a-c)]+(2b-c-a)/[(b-c)(b-a)]+(2c-a-b)/[(c-a)(c-b)]
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![1)已知分式3/(x^2+3x+1)=3/8,求1/(2x^2+6x-3)的值.2)已知x^2-5x-2009=0,求[(x-2)^3-(x-1)^2+1]/x-2的值.3)(2a-b-c)/[(a-b)(a-c)]+(2b-c-a)/[(b-c)(b-a)]+(2c-a-b)/[(c-a)(c-b)]](/uploads/image/z/603480-48-0.jpg?t=1%EF%BC%89%E5%B7%B2%E7%9F%A5%E5%88%86%E5%BC%8F3%2F%EF%BC%88x%5E2%2B3x%2B1%EF%BC%89%3D3%2F8%2C%E6%B1%821%2F%EF%BC%882x%5E2%2B6x-3%EF%BC%89%E7%9A%84%E5%80%BC.2%EF%BC%89%E5%B7%B2%E7%9F%A5x%5E2-5x-2009%3D0%2C%E6%B1%82%5B%EF%BC%88x-2%EF%BC%89%5E3-%28x-1%29%5E2%2B1%5D%2Fx-2%E7%9A%84%E5%80%BC.3%EF%BC%89%282a-b-c%29%2F%5B%28a-b%29%28a-c%29%5D%2B%282b-c-a%29%2F%5B%28b-c%29%28b-a%29%5D%2B%282c-a-b%29%2F%5B%28c-a%29%28c-b%29%5D)
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