化简(x+1)(x-1)(x²-x+1)(x²+x+1)
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化简(x+1)(x-1)(x²-x+1)(x²+x+1)
化简(x+1)(x-1)(x²-x+1)(x²+x+1)
化简(x+1)(x-1)(x²-x+1)(x²+x+1)
=[(x+1)(x²-x+1)][(x-1)(x²+x+1)]=(x^3+1)(x^3-1)=x^6-1
x^6-1