(x-y+z)(-x+y+x)=[z+( )]X[ ]=z²-( )²已知x+x分之一=3,求(x-x分之一)²
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(x-y+z)(-x+y+x)=[z+( )]X[ ]=z²-( )²已知x+x分之一=3,求(x-x分之一)²
(x-y+z)(-x+y+x)=[z+( )]X[ ]=z²-( )²
已知x+x分之一=3,求(x-x分之一)²
(x-y+z)(-x+y+x)=[z+( )]X[ ]=z²-( )²已知x+x分之一=3,求(x-x分之一)²
你的题是不是错的啊
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