若x^2=x-1,则x^2008-x^2007+x^2006的值是?

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若x^2=x-1,则x^2008-x^2007+x^2006的值是?
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若x^2=x-1,则x^2008-x^2007+x^2006的值是?
若x^2=x-1,则x^2008-x^2007+x^2006的值是?

若x^2=x-1,则x^2008-x^2007+x^2006的值是?

 
  新年快乐!

x^2=x-1
x^2-x=-1
x^2008-x^2007+x^2006
=x^2006X(x^2-x+1)
=x^2006X(-1+1)
=x^2006X0
=0


将x^2=x-1 代入 x^2008-x^2007+x^2006 可得:
(x-1)^1004-(X-1)^1003*x + (x-1)^1003
=(x-1)^1004-[(x-1)^1003*x - (x-1)^1003]
=(x-1)^1004-(x-1)^1003 * (x-1)
=(x-1)^1004-(x-1)^1004
=0

即x²-x+1=0
所以原式=x^2006(x²-x+1)=0