求一道数学题中的一步的解释已知圆(x+1)^2+(y-1)^2=1,圆C2与圆C1关于直线x-y-1=0对称,则圆C2的方程为答案设圆心(a,b)联立①y-1/x+2=-1②(x-2/2)-(y+1/2)+1=0解出圆心坐标上面写错了,答案
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![求一道数学题中的一步的解释已知圆(x+1)^2+(y-1)^2=1,圆C2与圆C1关于直线x-y-1=0对称,则圆C2的方程为答案设圆心(a,b)联立①y-1/x+2=-1②(x-2/2)-(y+1/2)+1=0解出圆心坐标上面写错了,答案](/uploads/image/z/6117280-16-0.jpg?t=%E6%B1%82%E4%B8%80%E9%81%93%E6%95%B0%E5%AD%A6%E9%A2%98%E4%B8%AD%E7%9A%84%E4%B8%80%E6%AD%A5%E7%9A%84%E8%A7%A3%E9%87%8A%E5%B7%B2%E7%9F%A5%E5%9C%86%EF%BC%88x%2B1%EF%BC%89%5E2%2B%EF%BC%88y-1%EF%BC%89%5E2%3D1%2C%E5%9C%86C2%E4%B8%8E%E5%9C%86C1%E5%85%B3%E4%BA%8E%E7%9B%B4%E7%BA%BFx-y-1%3D0%E5%AF%B9%E7%A7%B0%2C%E5%88%99%E5%9C%86C2%E7%9A%84%E6%96%B9%E7%A8%8B%E4%B8%BA%E7%AD%94%E6%A1%88%E8%AE%BE%E5%9C%86%E5%BF%83%EF%BC%88a%2Cb%EF%BC%89%E8%81%94%E7%AB%8B%E2%91%A0y-1%2Fx%2B2%3D-1%E2%91%A1%EF%BC%88x-2%2F2%EF%BC%89-%EF%BC%88y%2B1%2F2%EF%BC%89%2B1%3D0%E8%A7%A3%E5%87%BA%E5%9C%86%E5%BF%83%E5%9D%90%E6%A0%87%E4%B8%8A%E9%9D%A2%E5%86%99%E9%94%99%E4%BA%86%EF%BC%8C%E7%AD%94%E6%A1%88)
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