已知斜率为1的直线l过椭圆x^2/4+y^2=1已知斜率为1的直线L经过椭圆X^2/4+Y^2=1的右焦点,交椭圆于A、B,求弦长AB?算出直线方程是y=x-根号3,代入之后求出X1+X2=-8根号3/5,x1x2=8/5.根据这个可求x1-x2.这不就
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![已知斜率为1的直线l过椭圆x^2/4+y^2=1已知斜率为1的直线L经过椭圆X^2/4+Y^2=1的右焦点,交椭圆于A、B,求弦长AB?算出直线方程是y=x-根号3,代入之后求出X1+X2=-8根号3/5,x1x2=8/5.根据这个可求x1-x2.这不就](/uploads/image/z/6234135-15-5.jpg?t=%E5%B7%B2%E7%9F%A5%E6%96%9C%E7%8E%87%E4%B8%BA1%E7%9A%84%E7%9B%B4%E7%BA%BFl%E8%BF%87%E6%A4%AD%E5%9C%86x%5E2%2F4%2By%5E2%3D1%E5%B7%B2%E7%9F%A5%E6%96%9C%E7%8E%87%E4%B8%BA1%E7%9A%84%E7%9B%B4%E7%BA%BFL%E7%BB%8F%E8%BF%87%E6%A4%AD%E5%9C%86X%5E2%2F4%2BY%5E2%3D1%E7%9A%84%E5%8F%B3%E7%84%A6%E7%82%B9%2C%E4%BA%A4%E6%A4%AD%E5%9C%86%E4%BA%8EA%E3%80%81B%2C%E6%B1%82%E5%BC%A6%E9%95%BFAB%3F%E7%AE%97%E5%87%BA%E7%9B%B4%E7%BA%BF%E6%96%B9%E7%A8%8B%E6%98%AFy%3Dx-%E6%A0%B9%E5%8F%B73%2C%E4%BB%A3%E5%85%A5%E4%B9%8B%E5%90%8E%E6%B1%82%E5%87%BAX1%2BX2%3D-8%E6%A0%B9%E5%8F%B73%2F5%2Cx1x2%3D8%2F5.%E6%A0%B9%E6%8D%AE%E8%BF%99%E4%B8%AA%E5%8F%AF%E6%B1%82x1-x2.%E8%BF%99%E4%B8%8D%E5%B0%B1)
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