初二数学函数问题,求解答.已知:直线AB:y=2x-8与x、y轴交于A、B两点(1)若C为x轴上一点,且三角形ABC面积为32,求C点坐标(2)若过C点的直线L与直线y=2x+8的夹角为45度,求直线L的解析式.主要解
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![初二数学函数问题,求解答.已知:直线AB:y=2x-8与x、y轴交于A、B两点(1)若C为x轴上一点,且三角形ABC面积为32,求C点坐标(2)若过C点的直线L与直线y=2x+8的夹角为45度,求直线L的解析式.主要解](/uploads/image/z/62806-22-6.jpg?t=%E5%88%9D%E4%BA%8C%E6%95%B0%E5%AD%A6%E5%87%BD%E6%95%B0%E9%97%AE%E9%A2%98%2C%E6%B1%82%E8%A7%A3%E7%AD%94.%E5%B7%B2%E7%9F%A5%EF%BC%9A%E7%9B%B4%E7%BA%BFAB%EF%BC%9Ay%3D2x-8%E4%B8%8Ex%E3%80%81y%E8%BD%B4%E4%BA%A4%E4%BA%8EA%E3%80%81B%E4%B8%A4%E7%82%B9%EF%BC%881%EF%BC%89%E8%8B%A5C%E4%B8%BAx%E8%BD%B4%E4%B8%8A%E4%B8%80%E7%82%B9%2C%E4%B8%94%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E9%9D%A2%E7%A7%AF%E4%B8%BA32%2C%E6%B1%82C%E7%82%B9%E5%9D%90%E6%A0%87%EF%BC%882%EF%BC%89%E8%8B%A5%E8%BF%87C%E7%82%B9%E7%9A%84%E7%9B%B4%E7%BA%BFL%E4%B8%8E%E7%9B%B4%E7%BA%BFy%3D2x%2B8%E7%9A%84%E5%A4%B9%E8%A7%92%E4%B8%BA45%E5%BA%A6%2C%E6%B1%82%E7%9B%B4%E7%BA%BFL%E7%9A%84%E8%A7%A3%E6%9E%90%E5%BC%8F.%E4%B8%BB%E8%A6%81%E8%A7%A3)
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