若a²b²+a²+b²+1-2ab,则a+b的值为A.2 B.-2 C.2或-2 D.2或-2或0对不起我弄错了,应该是a²b²+a²+b²+1-2ab=2ab
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![若a²b²+a²+b²+1-2ab,则a+b的值为A.2 B.-2 C.2或-2 D.2或-2或0对不起我弄错了,应该是a²b²+a²+b²+1-2ab=2ab](/uploads/image/z/631746-18-6.jpg?t=%E8%8B%A5a%26%23178%3Bb%26%23178%3B%2Ba%26%23178%3B%2Bb%26%23178%3B%2B1-2ab%2C%E5%88%99a%2Bb%E7%9A%84%E5%80%BC%E4%B8%BAA.2+B.-2+C.2%E6%88%96-2+D.2%E6%88%96-2%E6%88%960%E5%AF%B9%E4%B8%8D%E8%B5%B7%E6%88%91%E5%BC%84%E9%94%99%E4%BA%86%EF%BC%8C%E5%BA%94%E8%AF%A5%E6%98%AFa%26%23178%3Bb%26%23178%3B%2Ba%26%23178%3B%2Bb%26%23178%3B%2B1-2ab%EF%BC%9D2ab)
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若a²b²+a²+b²+1-2ab,则a+b的值为A.2 B.-2 C.2或-2 D.2或-2或0对不起我弄错了,应该是a²b²+a²+b²+1-2ab=2ab
若a²b²+a²+b²+1-2ab,则a+b的值为
A.2 B.-2 C.2或-2 D.2或-2或0
对不起我弄错了,应该是a²b²+a²+b²+1-2ab=2ab
若a²b²+a²+b²+1-2ab,则a+b的值为A.2 B.-2 C.2或-2 D.2或-2或0对不起我弄错了,应该是a²b²+a²+b²+1-2ab=2ab
好了.我来回答.
a²b²+a²+b²+1-2ab=2ab
(ab-1)²+(a-b) ²=0
所以 ab=1 a=b
所以a=b=1或a=b=-1
所以a+b=2或-2
选C
代数式是不是得有个结果啊
(a-b)²+(ab-1)²=0
a=b,ab=1
故a=b=±1
选C
这个题目不对吧?
指数是x还是2,看不太清楚