若 x+2y+3z=10,4x+3y+2z=15,则x+y+z=?.

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若 x+2y+3z=10,4x+3y+2z=15,则x+y+z=?.
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若 x+2y+3z=10,4x+3y+2z=15,则x+y+z=?.
若 x+2y+3z=10,4x+3y+2z=15,则x+y+z=?.

若 x+2y+3z=10,4x+3y+2z=15,则x+y+z=?.
x+2y+3z=10,4x+3y+2z=15
两式相加,得
x+2y+3z+4x+3y+2z=10+15
5x+5y+5z=25
5(x+y+z)=25
x+y+z=5

x+2y+3z+4x+3y+2z
=5x+5y+5z
=10+15
=25
x+y+z
=25/5
=5

你好！
x+2y+3z+4x+3y+2z
=5x+5y+5z
=5（x+y+z）=10+15=25
所以x+y+z=25÷5=5
希望我的回答对你有所帮助。

0.0

x+2y+3z+4x+3y+2z
=5x+5y+5z
=10+15
=25
x+y+z
=25/5
=5

x+2y+3z=10,4x+3y+2z=15
两式相加，得
x+2y+3z+4x+3y+2z=10+15
5x+5y+5z=25
5(x+y+z)=25
x+y+z=5

将上述两式相加，即得：5x+5y+5z=25
等式两边分别除以5，可得：x+y+z=5

5

x+2y+3Z=10,
4x+3y+2z=15
两式相加
5（x+y+z）=25
x+y+z=5

(4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=? (4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuaihuajian 2x+z=10 x+y-z=4 3x-y-z=0 {2x+y=10 {x-y+z=4 {3x-y-z=0 (4x-2y-z)-{5x-[8y-2z-(x+y)]-2(3y-10z)}=?好难啊 若x+y+z=3y=2z,则x/x+y+z=? x+2y=3x+2z=4y+z 求x:y:z x+y/2=z+x/3=y+z/4 x+y+z=27 试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y) 已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z x+2y+3z=10,x-y+4z=10,x+3y+2z=2 x+2y+3z=10,x-y+4z=10,x+3y+2z=2 x-y+4z=10,x+3y+2z=2,x+2y+3z=11. x+y+z=4 2x+3y-z=6 3x+2y+2z=10 4x+y+z=-3 2x+3y-4z=-10 x+2y-z=-1 若x/2=y/3=z/4,则3x-2y+5z/x+y+z= x+2y+3z=10,4x+3y+2z=15则x+y+z= x+2y+3Z=10,4x+3y+2z=15,求x+y+z=