定义函数total(n),计算1+2+3+...+n,函数返回类型是int.在主函数中输入正整数n,调用函数total(n)计算并输出下列算式的值.S=1+1/(1+2)+1/(1+2+3)+...+1/(1+2+3+...+n)我的答案是:#include int total(int x){int z=0;for(;x>
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![定义函数total(n),计算1+2+3+...+n,函数返回类型是int.在主函数中输入正整数n,调用函数total(n)计算并输出下列算式的值.S=1+1/(1+2)+1/(1+2+3)+...+1/(1+2+3+...+n)我的答案是:#include int total(int x){int z=0;for(;x>](/uploads/image/z/649980-36-0.jpg?t=%E5%AE%9A%E4%B9%89%E5%87%BD%E6%95%B0total%28n%29%2C%E8%AE%A1%E7%AE%971%2B2%2B3%2B...%2Bn%2C%E5%87%BD%E6%95%B0%E8%BF%94%E5%9B%9E%E7%B1%BB%E5%9E%8B%E6%98%AFint.%E5%9C%A8%E4%B8%BB%E5%87%BD%E6%95%B0%E4%B8%AD%E8%BE%93%E5%85%A5%E6%AD%A3%E6%95%B4%E6%95%B0n%2C%E8%B0%83%E7%94%A8%E5%87%BD%E6%95%B0total%28n%29%E8%AE%A1%E7%AE%97%E5%B9%B6%E8%BE%93%E5%87%BA%E4%B8%8B%E5%88%97%E7%AE%97%E5%BC%8F%E7%9A%84%E5%80%BC.S%3D1%2B1%2F%281%2B2%29%2B1%2F%281%2B2%2B3%29%2B...%2B1%2F%281%2B2%2B3%2B...%2Bn%29%E6%88%91%E7%9A%84%E7%AD%94%E6%A1%88%E6%98%AF%EF%BC%9A%23include+int+total%28int+x%29%7Bint+z%3D0%3Bfor%28%3Bx%3E)
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