1*2/1+2*3/1+3*4/1+.98*99/1+99*100/1=?
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1*2/1+2*3/1+3*4/1+.98*99/1+99*100/1=?
1*2/1+2*3/1+3*4/1+.98*99/1+99*100/1=?
1*2/1+2*3/1+3*4/1+.98*99/1+99*100/1=?
你是不是写错了?
应该是 :1/1*2+1/2*3+1/3*4+.1/98*99+1/99*100吧
1/1*2+1/2*3+1/3*4+.1/98*99+1/99*100
=(1/1-1/2)+(1/2-1/3)+(1/3-1/4)+……+(1/98-1/99)+(1/99-1/100)
=1/1-1/2+1/2-1/3+1/3-1/4+……+1/98-1/99+1/99-1/100
=1/1-1/100
=99/100
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|1-1/2|-|1/2-1/3|-|1/3-1/4|-.-|1/9-1/10|
|1-1/2|+|1/2-1/3|+|1/3-1/4|+...|1/9-1/10|
1:8 2:9 1:9 3:4 1:3 ...
/1/3-1/2/+/1/4-1/3/+/1/5-1/4/+.+/1/10-1/9/
|1/3-1/2|+|1/4-1/3|+|1/5-1/4|+...+|1/10-1/9|
1*2/1+2*3/1+3*4/1+...+8*9/1+9*10/1简算
有理数:-1/2+1/3-(-1/9)-1/4=
1/1*3+1/2*4+...+1/9*11=?
1/1*2*3+1/2*3*4+1/3*4*5+.+1/8*9*10
(1-1/2^2)*(1-1/3)*(1-1/4^2)*…*(1-1/9^2)*(1/10^2)
(1+1/2)*(1+1/4)*.*(1+1/10)*(1-1/3)*(1-1/5)*.(1-1/9)简算
1×2/1+1×2+2×3/1+…+1×2+2×3+3×4+…9×10/1
1+2+3+.9
lim(1+1/3+1/9+...+1/3^(n1))/(1+1/2+1/4+...+1/2^(n-1))
lim(1+1/3+1/9+...+1/3^(n1))/(1+1/2+1/4+...+1/2^(n-1))急
|3/1-2/1|+|4/1-3/1|+|5/1-4/1|+...+|10/1-9/1|=?3Q
9*(1-1/2)*(1-1/3)*(1-1/4)*(1-1/5)*(1-1/6)*(1-1/7)*(1-1/8)*(1-1/9)怎样简便计算
((1/2)-1)*((1/3)-1)*((1/4)-1)*((1/5)-1)*((1/6)-1)*((1/7)-1)*((1/8)-1)*((1/9)-1)*((1/10)-1)