已知sin(a+π/3)+sina=-4√3/5,-π/2

来源:学生作业帮助网 编辑:作业帮 时间:2024/10/04 13:39:14
已知sin(a+π/3)+sina=-4√3/5,-π/2
x 09c,c; qA *% 3P@CA쀈X;"Bʾ{矴Ȫޕ̥aΊ\:NYd?_=/Ӓ0aM'i4j "7zV1};m( 5@ڪ'zKR  I$1W'xiJ3/B-7̤3:

已知sin(a+π/3)+sina=-4√3/5,-π/2
已知sin(a+π/3)+sina=-4√3/5,-π/2

已知sin(a+π/3)+sina=-4√3/5,-π/2
sin(a+π/3)+sina=-4√3/5
sinacosπ/3+cosasinπ/3+sina=-4√3/5
(3/2)sina+(√3/2)cosa=-4√3/5
sina=(2/3)*(-4√3/5-√3/2*cosa)=-(8√3/15+√3/3*cosa)
代入(sina)^2+(cosa)^2=1
令x=cosa
[-(8√3/15+√3/3*x)]^2+x^2=1
64/75+16x/15+x^2/3+x^2=1
(4/3)x^2+(16/15)x-11/75=0
x=(-4±3√3)/10
-π/2