设f(α)=(2sinαcosα+cosα)/[(1+sin^2α+cos(3/2π+α)-sin^2(π/2+α)](1+sinα≠0)(1)化简f(α)(2)求f(1°)+f(2°)+f(3°)+……+f(89°)不好意思,第二问是求f(1°)*f(2°)*f(3°)*……*f(89°)
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/29 06:08:09
![设f(α)=(2sinαcosα+cosα)/[(1+sin^2α+cos(3/2π+α)-sin^2(π/2+α)](1+sinα≠0)(1)化简f(α)(2)求f(1°)+f(2°)+f(3°)+……+f(89°)不好意思,第二问是求f(1°)*f(2°)*f(3°)*……*f(89°)](/uploads/image/z/665953-25-3.jpg?t=%E8%AE%BEf%28%CE%B1%29%3D%282sin%CE%B1cos%CE%B1%2Bcos%CE%B1%29%2F%5B%281%2Bsin%5E2%CE%B1%2Bcos%283%2F2%CF%80%2B%CE%B1%29-sin%5E2%28%CF%80%2F2%2B%CE%B1%29%5D%281%2Bsin%CE%B1%E2%89%A00%29%EF%BC%881%EF%BC%89%E5%8C%96%E7%AE%80f%EF%BC%88%CE%B1%EF%BC%89%EF%BC%882%EF%BC%89%E6%B1%82f%EF%BC%881%C2%B0%EF%BC%89%2Bf%EF%BC%882%C2%B0%EF%BC%89%2Bf%EF%BC%883%C2%B0%EF%BC%89%2B%E2%80%A6%E2%80%A6%2Bf%EF%BC%8889%C2%B0%EF%BC%89%E4%B8%8D%E5%A5%BD%E6%84%8F%E6%80%9D%EF%BC%8C%E7%AC%AC%E4%BA%8C%E9%97%AE%E6%98%AF%E6%B1%82f%EF%BC%881%C2%B0%EF%BC%89%2Af%EF%BC%882%C2%B0%EF%BC%89%2Af%EF%BC%883%C2%B0%EF%BC%89%2A%E2%80%A6%E2%80%A6%2Af%EF%BC%8889%C2%B0%EF%BC%89)
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来源:学生作业帮助网 编辑:作业帮 时间:2024/08/29 06:08:09