在四边形ABCD中AB平行CD,E丶F是对角线AC上的两点,AE=CF,求证三角形ABE全等于三角形CDF,BE平行于DF
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![在四边形ABCD中AB平行CD,E丶F是对角线AC上的两点,AE=CF,求证三角形ABE全等于三角形CDF,BE平行于DF](/uploads/image/z/6693973-61-3.jpg?t=%E5%9C%A8%E5%9B%9B%E8%BE%B9%E5%BD%A2ABCD%E4%B8%ADAB%E5%B9%B3%E8%A1%8CCD%2CE%E4%B8%B6F%E6%98%AF%E5%AF%B9%E8%A7%92%E7%BA%BFAC%E4%B8%8A%E7%9A%84%E4%B8%A4%E7%82%B9%2CAE%3DCF%2C%E6%B1%82%E8%AF%81%E4%B8%89%E8%A7%92%E5%BD%A2ABE%E5%85%A8%E7%AD%89%E4%BA%8E%E4%B8%89%E8%A7%92%E5%BD%A2CDF%2CBE%E5%B9%B3%E8%A1%8C%E4%BA%8EDF)
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