已知y=根号x-2+根号2-x+3/4 ,则根号xy =

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已知y=根号x-2+根号2-x+3/4 ,则根号xy =
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已知y=根号x-2+根号2-x+3/4 ,则根号xy =
已知y=根号x-2+根号2-x+3/4 ,则根号xy =

已知y=根号x-2+根号2-x+3/4 ,则根号xy =
求函数的定义域可知:x-2≥0,2-x≥0,可知,x=2
则 y=根号x-2+根号2-x+3/4=3/4,
∴ xy = 2×3/4=3/2

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