已知函数f(x)=4sin2x+4cosx-a,x∈R(1)若f(π/3)=0,求a的值(2)当x∈[-π/4,2π/3]时f(x)=0恒有解,求实数a的范围(3)若函数y=log1/2[f(x)+a(1+cosx)]的最小值为-3,求a的值f(x)=4sin^2x+4cosx-a
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![已知函数f(x)=4sin2x+4cosx-a,x∈R(1)若f(π/3)=0,求a的值(2)当x∈[-π/4,2π/3]时f(x)=0恒有解,求实数a的范围(3)若函数y=log1/2[f(x)+a(1+cosx)]的最小值为-3,求a的值f(x)=4sin^2x+4cosx-a](/uploads/image/z/6787012-4-2.jpg?t=%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%28x%29%3D4sin2x%2B4cosx-a%2Cx%E2%88%88R%281%29%E8%8B%A5f%28%CF%80%2F3%29%3D0%2C%E6%B1%82a%E7%9A%84%E5%80%BC%EF%BC%882%EF%BC%89%E5%BD%93x%E2%88%88%5B-%CF%80%2F4%2C2%CF%80%2F3%5D%E6%97%B6f%28x%29%3D0%E6%81%92%E6%9C%89%E8%A7%A3%2C%E6%B1%82%E5%AE%9E%E6%95%B0a%E7%9A%84%E8%8C%83%E5%9B%B4%EF%BC%883%29%E8%8B%A5%E5%87%BD%E6%95%B0y%3Dlog1%2F2%5Bf%28x%29%2Ba%281%2Bcosx%29%5D%E7%9A%84%E6%9C%80%E5%B0%8F%E5%80%BC%E4%B8%BA-3%2C%E6%B1%82a%E7%9A%84%E5%80%BCf%28x%29%3D4sin%5E2x%2B4cosx-a)
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