cos(a+b)=sin(a-b) 求tan a
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cos(a+b)=sin(a-b) 求tan a
cos(a+b)=sin(a-b) 求tan a
cos(a+b)=sin(a-b) 求tan a
cos(a+b)=cosa*cosb-sina*sinb
sin(a-b)=sina*cosb-cosa*sinb
合并一下得sina*(cosb+sinb)=cosa*(sinb+cosb)
所以,当sinb+cosb不为零,即b不为kπ/2-π/4时则有tana=1
若b=kπ/2-π/4,则tana为任意实数
cos∧a-cos∧b=t则sin(a+b)sin(a-b)=
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