如图,△ABC中,AC>AB,在AC上取CD=AB,M为AD的中点,N是BC中点,延长NM交BA的延长线于E.求证:AM=AE.希望能用两种方法解,一种是中位线,一种是倍长中线.
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![如图,△ABC中,AC>AB,在AC上取CD=AB,M为AD的中点,N是BC中点,延长NM交BA的延长线于E.求证:AM=AE.希望能用两种方法解,一种是中位线,一种是倍长中线.](/uploads/image/z/6871656-48-6.jpg?t=%E5%A6%82%E5%9B%BE%2C%E2%96%B3ABC%E4%B8%AD%2CAC%3EAB%2C%E5%9C%A8AC%E4%B8%8A%E5%8F%96CD%3DAB%2CM%E4%B8%BAAD%E7%9A%84%E4%B8%AD%E7%82%B9%2CN%E6%98%AFBC%E4%B8%AD%E7%82%B9%2C%E5%BB%B6%E9%95%BFNM%E4%BA%A4BA%E7%9A%84%E5%BB%B6%E9%95%BF%E7%BA%BF%E4%BA%8EE.%E6%B1%82%E8%AF%81%EF%BC%9AAM%3DAE.%E5%B8%8C%E6%9C%9B%E8%83%BD%E7%94%A8%E4%B8%A4%E7%A7%8D%E6%96%B9%E6%B3%95%E8%A7%A3%2C%E4%B8%80%E7%A7%8D%E6%98%AF%E4%B8%AD%E4%BD%8D%E7%BA%BF%2C%E4%B8%80%E7%A7%8D%E6%98%AF%E5%80%8D%E9%95%BF%E4%B8%AD%E7%BA%BF.)
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