如图,在△ABC中,E为BC中点,AD平分∠BAC,EF‖AD.EF与CA的延长线交于F,与AB交于H,试说明BH=CF的理由
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![如图,在△ABC中,E为BC中点,AD平分∠BAC,EF‖AD.EF与CA的延长线交于F,与AB交于H,试说明BH=CF的理由](/uploads/image/z/6871768-16-8.jpg?t=%E5%A6%82%E5%9B%BE%2C%E5%9C%A8%E2%96%B3ABC%E4%B8%AD%2CE%E4%B8%BABC%E4%B8%AD%E7%82%B9%2CAD%E5%B9%B3%E5%88%86%E2%88%A0BAC%2CEF%E2%80%96AD.EF%E4%B8%8ECA%E7%9A%84%E5%BB%B6%E9%95%BF%E7%BA%BF%E4%BA%A4%E4%BA%8EF%2C%E4%B8%8EAB%E4%BA%A4%E4%BA%8EH%2C%E8%AF%95%E8%AF%B4%E6%98%8EBH%3DCF%E7%9A%84%E7%90%86%E7%94%B1)
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