期末复习(1)三角与向量(5)若点O为△ABC的外心,点H为垂心,向量OH=m(向量OA+向量OB+向量OC),则m= 下面解答中“一个三角形的垂心到一个顶点的距离等于它的外心到对边中点距离的两倍.”为什
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![期末复习(1)三角与向量(5)若点O为△ABC的外心,点H为垂心,向量OH=m(向量OA+向量OB+向量OC),则m= 下面解答中“一个三角形的垂心到一个顶点的距离等于它的外心到对边中点距离的两倍.”为什](/uploads/image/z/6872601-57-1.jpg?t=%E6%9C%9F%E6%9C%AB%E5%A4%8D%E4%B9%A0%EF%BC%881%EF%BC%89%E4%B8%89%E8%A7%92%E4%B8%8E%E5%90%91%E9%87%8F%EF%BC%885%EF%BC%89%E8%8B%A5%E7%82%B9O%E4%B8%BA%E2%96%B3ABC%E7%9A%84%E5%A4%96%E5%BF%83%2C%E7%82%B9H%E4%B8%BA%E5%9E%82%E5%BF%83%2C%E5%90%91%E9%87%8FOH%3Dm%28%E5%90%91%E9%87%8FOA%2B%E5%90%91%E9%87%8FOB%2B%E5%90%91%E9%87%8FOC%29%2C%E5%88%99m%3D+%E4%B8%8B%E9%9D%A2%E8%A7%A3%E7%AD%94%E4%B8%AD%E2%80%9C%E4%B8%80%E4%B8%AA%E4%B8%89%E8%A7%92%E5%BD%A2%E7%9A%84%E5%9E%82%E5%BF%83%E5%88%B0%E4%B8%80%E4%B8%AA%E9%A1%B6%E7%82%B9%E7%9A%84%E8%B7%9D%E7%A6%BB%E7%AD%89%E4%BA%8E%E5%AE%83%E7%9A%84%E5%A4%96%E5%BF%83%E5%88%B0%E5%AF%B9%E8%BE%B9%E4%B8%AD%E7%82%B9%E8%B7%9D%E7%A6%BB%E7%9A%84%E4%B8%A4%E5%80%8D.%E2%80%9D%E4%B8%BA%E4%BB%80)
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