已知如图,△ABC中AB=AC,AE是角平分线,BM平分∠ABC交AE于点M,经过B、M两点的⊙O交BC于G,交AB于点F,FB
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![已知如图,△ABC中AB=AC,AE是角平分线,BM平分∠ABC交AE于点M,经过B、M两点的⊙O交BC于G,交AB于点F,FB](/uploads/image/z/6876066-66-6.jpg?t=%E5%B7%B2%E7%9F%A5%E5%A6%82%E5%9B%BE%2C%E2%96%B3ABC%E4%B8%ADAB%3DAC%2CAE%E6%98%AF%E8%A7%92%E5%B9%B3%E5%88%86%E7%BA%BF%2CBM%E5%B9%B3%E5%88%86%E2%88%A0ABC%E4%BA%A4AE%E4%BA%8E%E7%82%B9M%2C%E7%BB%8F%E8%BF%87B%E3%80%81M%E4%B8%A4%E7%82%B9%E7%9A%84%E2%8A%99O%E4%BA%A4BC%E4%BA%8EG%2C%E4%BA%A4AB%E4%BA%8E%E7%82%B9F%2CFB)
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