1,二次函数y=x2-bx+2的对称轴为直线X=2,则b=?2,把二次函数y=x²-2x-1配方成顶点式为?3,二次函数的图像的顶点坐标为(-2,3),其形状,开口方向与抛物线y=-x²相同,这个二次函数解析式为?4,抛物
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/07 11:32:26
![1,二次函数y=x2-bx+2的对称轴为直线X=2,则b=?2,把二次函数y=x²-2x-1配方成顶点式为?3,二次函数的图像的顶点坐标为(-2,3),其形状,开口方向与抛物线y=-x²相同,这个二次函数解析式为?4,抛物](/uploads/image/z/6890258-2-8.jpg?t=1%2C%E4%BA%8C%E6%AC%A1%E5%87%BD%E6%95%B0y%3Dx2-bx%2B2%E7%9A%84%E5%AF%B9%E7%A7%B0%E8%BD%B4%E4%B8%BA%E7%9B%B4%E7%BA%BFX%3D2%2C%E5%88%99b%3D%3F2%2C%E6%8A%8A%E4%BA%8C%E6%AC%A1%E5%87%BD%E6%95%B0y%3Dx%26%23178%3B-2x-1%E9%85%8D%E6%96%B9%E6%88%90%E9%A1%B6%E7%82%B9%E5%BC%8F%E4%B8%BA%3F3%2C%E4%BA%8C%E6%AC%A1%E5%87%BD%E6%95%B0%E7%9A%84%E5%9B%BE%E5%83%8F%E7%9A%84%E9%A1%B6%E7%82%B9%E5%9D%90%E6%A0%87%E4%B8%BA%EF%BC%88-2%2C3%EF%BC%89%2C%E5%85%B6%E5%BD%A2%E7%8A%B6%2C%E5%BC%80%E5%8F%A3%E6%96%B9%E5%90%91%E4%B8%8E%E6%8A%9B%E7%89%A9%E7%BA%BFy%3D-x%26%23178%3B%E7%9B%B8%E5%90%8C%2C%E8%BF%99%E4%B8%AA%E4%BA%8C%E6%AC%A1%E5%87%BD%E6%95%B0%E8%A7%A3%E6%9E%90%E5%BC%8F%E4%B8%BA%3F4%2C%E6%8A%9B%E7%89%A9)
xN@_`J4p+{
M
j#,Xa)+^(0QLs{鄈^נ'Gb!1BK-v5۴7XS0b%$1"qa^\^Y*91uNli$c<r:;eg,ʑ]0|WT י,O4nTFkjZ`;8ݤۨs#*x\R7*]'I3Gzq.BuwP"<&$h:!oϦM