简单的一个不定积分问题如果被积函数含有 【(x^2-a^2)开根号】的式子,常可设为x=asect,t∈(0,π/2).怎么不设为t∈(-π/2,π/2),我知道是想使得tant为正,但是不这么设的话,会少情况的呀.没有包
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/02 03:41:02
![简单的一个不定积分问题如果被积函数含有 【(x^2-a^2)开根号】的式子,常可设为x=asect,t∈(0,π/2).怎么不设为t∈(-π/2,π/2),我知道是想使得tant为正,但是不这么设的话,会少情况的呀.没有包](/uploads/image/z/6891455-47-5.jpg?t=%E7%AE%80%E5%8D%95%E7%9A%84%E4%B8%80%E4%B8%AA%E4%B8%8D%E5%AE%9A%E7%A7%AF%E5%88%86%E9%97%AE%E9%A2%98%E5%A6%82%E6%9E%9C%E8%A2%AB%E7%A7%AF%E5%87%BD%E6%95%B0%E5%90%AB%E6%9C%89+%E3%80%90%EF%BC%88x%5E2-a%5E2%EF%BC%89%E5%BC%80%E6%A0%B9%E5%8F%B7%E3%80%91%E7%9A%84%E5%BC%8F%E5%AD%90%2C%E5%B8%B8%E5%8F%AF%E8%AE%BE%E4%B8%BAx%3Dasect%2Ct%E2%88%88%280%2C%CF%80%2F2%EF%BC%89.%E6%80%8E%E4%B9%88%E4%B8%8D%E8%AE%BE%E4%B8%BAt%E2%88%88%28-%CF%80%2F2%2C%CF%80%2F2%EF%BC%89%2C%E6%88%91%E7%9F%A5%E9%81%93%E6%98%AF%E6%83%B3%E4%BD%BF%E5%BE%97tant%E4%B8%BA%E6%AD%A3%2C%E4%BD%86%E6%98%AF%E4%B8%8D%E8%BF%99%E4%B9%88%E8%AE%BE%E7%9A%84%E8%AF%9D%2C%E4%BC%9A%E5%B0%91%E6%83%85%E5%86%B5%E7%9A%84%E5%91%80.%E6%B2%A1%E6%9C%89%E5%8C%85)
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