sin(0+75)+cos(0+45)-√3cos(0+15)上面的数值是度 0是希答``

若绝对值cos/cos+sin/绝对值sin=0,试判断sin（cos）*cos（sin）的符号 已知sinα+sinβ+sinγ=0,cosα+cosβ+cosγ=0.求cos(β sin(0+75)+cos(0+45)-√3cos(0+15)上面的数值是度 0是希答`` θ∈(0,π/2),比较cosθ、sin(cosθ)、cos(sinθ)的大小 非线性方程解析解-x0*cos(b)*cos(c)-y0*(-sin(a)*cos(b)*cos(c)-cos(a)*sin(c))-z0*(-cos(a)*cos(b)*cos(c)+sin(a)*sin(c))=0-x0*cos(b)*sin(c)-y0*(-sin(a)*cos(b)*sin(c)+cos(a)*cos(c))-z0*(-cos(a)*cos(b)*sin(c)-sin(a)*cos(c))=0 -x0*cos(b)-y0*sin(a)*co 若sinαsinβ+cosαcosβ=0,则sinαcosα+sinβcosβ= .1若sinαsinβ+cosαcosβ=0,则sinαcosα+sinβcosβ= 2已知sin(α+β)=1,则cos(α+2β)+sin(2α+β)=急, 求非线性方程组的“解析解”-x0*cos(b)*cos(c)-y0*(-sin(a)*cos(b)*cos(c)-cos(a)*sin(c))-z0*(-cos(a)*cos(b)*cos(c)+sin(a)*sin(c))=0 -x0*cos(b)*sin(c)-y0*(-sin(a)*cos(b)*sin(c)+cos(a)*cos(c))-z0*(-cos(a)*cos(b)*sin(c)-sin(a)*cos(c))=0 -x0*cos 若sinθ*cosθ>0,cosθ 已知sinα cosα >0,tanαcosα |sinα|/ sinα+cosα/|cosα|=0 ctg(sinα)tg(cosα) 0(< = >) 6sin^2α-sinαcosα-cos^2α=0,求cosα+sinα的值 已知sinθcosθ>0 sinθtanθ 已知sin&cos&=60/169(0 已知sin+cos=1/5(0 若sin@cos@=1/8 (0 2/sinθ+3/cosθ（0 求解三角函数sin a>-cos a (0 若sin∝>0,cos∝