1.2sin2x-sinxcosx-cosx2=12.7cosx+3cos2x=03.sin2x/cos2x=cos2x/sinx4.(1+sinx)/(1+cosx)=1/2不好意思,第一题写错了,应该2sin2x+-sinxcosx-cos2=1
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![1.2sin2x-sinxcosx-cosx2=12.7cosx+3cos2x=03.sin2x/cos2x=cos2x/sinx4.(1+sinx)/(1+cosx)=1/2不好意思,第一题写错了,应该2sin2x+-sinxcosx-cos2=1](/uploads/image/z/6914088-0-8.jpg?t=1.2sin2x-sinxcosx-cosx2%3D12.7cosx%2B3cos2x%3D03.sin2x%2Fcos2x%3Dcos2x%2Fsinx4.%281%2Bsinx%29%2F%281%2Bcosx%29%3D1%2F2%E4%B8%8D%E5%A5%BD%E6%84%8F%E6%80%9D%2C%E7%AC%AC%E4%B8%80%E9%A2%98%E5%86%99%E9%94%99%E4%BA%86%2C%E5%BA%94%E8%AF%A52sin2x%2B-sinxcosx-cos2%3D1)
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1.2sin2x-sinxcosx-cosx2=12.7cosx+3cos2x=03.sin2x/cos2x=cos2x/sinx4.(1+sinx)/(1+cosx)=1/2不好意思,第一题写错了,应该2sin2x+-sinxcosx-cos2=1
1.2sin2x-sinxcosx-cosx2=1
2.7cosx+3cos2x=0
3.sin2x/cos2x=cos2x/sinx
4.(1+sinx)/(1+cosx)=1/2
不好意思,第一题写错了,应该2sin2x+-sinxcosx-cos2=1
1.2sin2x-sinxcosx-cosx2=12.7cosx+3cos2x=03.sin2x/cos2x=cos2x/sinx4.(1+sinx)/(1+cosx)=1/2不好意思,第一题写错了,应该2sin2x+-sinxcosx-cos2=1
“sin2x”是“sin(2x)”,还是“(sinx)^2”?“cosx2”又代表什么?
先把你的题目写得能让别人看懂吧
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1.2sin2x-sinxcosx-cosx2=12.7cosx+3cos2x=03.sin2x/cos2x=cos2x/sinx4.(1+sinx)/(1+cosx)=1/2不好意思,第一题写错了,应该2sin2x+-sinxcosx-cos2=1
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