MATLAB中fsolve解非线性方程问题clear all;clc;close all;N1=1;%N2=2;%%P1=750/1120;f=50;%%%%基值定义开始%定SacB=1120;%MVAUacB=550;%kVIacB=SacB/UacB/(sqrt(3));ZacB=UacB*UacB/SacB;%ohm%定义SdcB=1120;UdcB=250;K=UdcB/UacB;IdcB=sqrt(3)*IacB/
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