求到定点(2,0)与到定直线X=8的距离之比是根号2除以2的动点的轨迹方程设该轨迹上的点的坐标是(x,y) ∵到定点(2,0)的距离与到x=8的距离之比为2√2 ∴{√[(2-x)^2+y^2]}/(8-x)=2√2 ∴(2-x)^2+y^2=8(8-x)^2
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![求到定点(2,0)与到定直线X=8的距离之比是根号2除以2的动点的轨迹方程设该轨迹上的点的坐标是(x,y) ∵到定点(2,0)的距离与到x=8的距离之比为2√2 ∴{√[(2-x)^2+y^2]}/(8-x)=2√2 ∴(2-x)^2+y^2=8(8-x)^2](/uploads/image/z/6955260-60-0.jpg?t=%E6%B1%82%E5%88%B0%E5%AE%9A%E7%82%B9%282%2C0%29%E4%B8%8E%E5%88%B0%E5%AE%9A%E7%9B%B4%E7%BA%BFX%3D8%E7%9A%84%E8%B7%9D%E7%A6%BB%E4%B9%8B%E6%AF%94%E6%98%AF%E6%A0%B9%E5%8F%B72%E9%99%A4%E4%BB%A52%E7%9A%84%E5%8A%A8%E7%82%B9%E7%9A%84%E8%BD%A8%E8%BF%B9%E6%96%B9%E7%A8%8B%E8%AE%BE%E8%AF%A5%E8%BD%A8%E8%BF%B9%E4%B8%8A%E7%9A%84%E7%82%B9%E7%9A%84%E5%9D%90%E6%A0%87%E6%98%AF%28x%2Cy%29+%E2%88%B5%E5%88%B0%E5%AE%9A%E7%82%B9%EF%BC%882%2C0%EF%BC%89%E7%9A%84%E8%B7%9D%E7%A6%BB%E4%B8%8E%E5%88%B0x%3D8%E7%9A%84%E8%B7%9D%E7%A6%BB%E4%B9%8B%E6%AF%94%E4%B8%BA2%E2%88%9A2+%E2%88%B4%7B%E2%88%9A%5B%282-x%29%5E2%2By%5E2%5D%7D%2F%288-x%29%3D2%E2%88%9A2+%E2%88%B4%282-x%29%5E2%2By%5E2%3D8%288-x%29%5E2)
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