mn^2/2p^2÷-3m^2n^2/4pq
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mn^2/2p^2÷-3m^2n^2/4pq
mn^2/2p^2÷-3m^2n^2/4pq
mn^2/2p^2÷-3m^2n^2/4pq
原式=-mn²/2p²×4pq/3m²n²
=-2q/3mp
2m/3n×(3n/p)^2÷mn//p^22m/3n×(3n/p)^2÷mn/p^2答案是不是6
3n/2m•(p/3n)²÷p²/mn
3(m^2n+mn)-4(mn-2m^2n)+mn.要有过程
mn^2/2p^2÷-3m^2n^2/4pq
(-2m/3n)的3次方×(-3n/p)2÷mn/p2
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