已知函数f(x)=cos^2(x+π/3)-1/2,g(x)=1/2sin(2x+2π/3),经过怎样的变换?已知函数f(x)=cos^2(x+π/3)-1/2,g(x)=1/2sin(2x+2π/3),要得到fx只需要把gx的图像经过怎样的变换
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![已知函数f(x)=cos^2(x+π/3)-1/2,g(x)=1/2sin(2x+2π/3),经过怎样的变换?已知函数f(x)=cos^2(x+π/3)-1/2,g(x)=1/2sin(2x+2π/3),要得到fx只需要把gx的图像经过怎样的变换](/uploads/image/z/6964033-49-3.jpg?t=%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%28x%29%3Dcos%5E2%28x%2B%CF%80%2F3%29-1%2F2%2Cg%28x%29%3D1%2F2sin%282x%2B2%CF%80%2F3%29%2C%E7%BB%8F%E8%BF%87%E6%80%8E%E6%A0%B7%E7%9A%84%E5%8F%98%E6%8D%A2%3F%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%28x%29%3Dcos%5E2%28x%2B%CF%80%2F3%29-1%2F2%2Cg%28x%29%3D1%2F2sin%282x%2B2%CF%80%2F3%29%2C%E8%A6%81%E5%BE%97%E5%88%B0fx%E5%8F%AA%E9%9C%80%E8%A6%81%E6%8A%8Agx%E7%9A%84%E5%9B%BE%E5%83%8F%E7%BB%8F%E8%BF%87%E6%80%8E%E6%A0%B7%E7%9A%84%E5%8F%98%E6%8D%A2)
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已知函数f(x)=cos^2(x+π/3)-1/2,g(x)=1/2sin(2x+2π/3),经过怎样的变换?已知函数f(x)=cos^2(x+π/3)-1/2,g(x)=1/2sin(2x+2π/3),要得到fx只需要把gx的图像经过怎样的变换
已知函数f(x)=cos^2(x+π/3)-1/2,g(x)=1/2sin(2x+2π/3),经过怎样的变换?
已知函数f(x)=cos^2(x+π/3)-1/2,g(x)=1/2sin(2x+2π/3),
要得到fx只需要把gx的图像经过怎样的变换
已知函数f(x)=cos^2(x+π/3)-1/2,g(x)=1/2sin(2x+2π/3),经过怎样的变换?已知函数f(x)=cos^2(x+π/3)-1/2,g(x)=1/2sin(2x+2π/3),要得到fx只需要把gx的图像经过怎样的变换
f(x)=cos²(x+π/3)-1/2 = (1/2)·[2cos²(x+π/3)-1]
= (1/2)·cos(2x+2π/3)
g(x)变换到f(x)可用的方式:
1.g(x)向左平移 Kπ + π/4 个单位
2.g(x)向右平移 Kπ + 3π/4 个单位
将图像向左移4/π。
变成1/2sin(2(x+4/π)+2π/3),即为1/2cos(2x+2π/3)。即为cos^2(x+π/3)-1/2