△ABC中,AD平分∠BAC,BE⊥AD,M是BC中点,求证:ME‖AC.
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![△ABC中,AD平分∠BAC,BE⊥AD,M是BC中点,求证:ME‖AC.](/uploads/image/z/7021977-33-7.jpg?t=%E2%96%B3ABC%E4%B8%AD%2CAD%E5%B9%B3%E5%88%86%E2%88%A0BAC%2CBE%E2%8A%A5AD%2CM%E6%98%AFBC%E4%B8%AD%E7%82%B9%2C%E6%B1%82%E8%AF%81%EF%BC%9AME%E2%80%96AC.)
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