用卡诺图化简F(A,B,C,D)=∑(3,4,5,7,9,13,14,15)
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用卡诺图化简F(A,B,C,D)=∑(3,4,5,7,9,13,14,15)
用卡诺图化简F(A,B,C,D)=∑(3,4,5,7,9,13,14,15)
用卡诺图化简F(A,B,C,D)=∑(3,4,5,7,9,13,14,15)
CD 00 01 11 10
AB
00 0 0 1 0
01 1 1 1 0
11 0 1 1 1
10 0 1 0 0
化简为:BD+ AB~C + ACD + ABC + CD
字母前加~为非
用卡诺图化简F(A,B,C,D)=∑(3,4,5,7,9,13,14,15)
用卡诺图化简F(A,B,C,D)∑m(2,4,6,7,12,15)
请用卡诺图化简逻辑函数至最简与成式用卡诺图化简下列逻辑函数:F(A,B,C,D)=∑m(0,1,2,3,4,7,8,9,10,12,14,15)+∑d(5,13)
用卡诺图法化简F(A,B,C,D)=∑(2,3,6,7,8,10,12,14)
卡诺图化简 F(A,B,C,D) = ∑m(2,3,6,7,8,10,12,14),请画出卡诺图.
用卡诺图化简F(A,B,C,D)=∑(0,2,3,5,6,7,8,9)//(10,11,12)
用卡诺图化简逻辑函数Y=F(A,B,C,D)=Σm(3,4,5,7,9,13,14,15),
用卡诺图化简 F(A,B,C)=∑m(1,2,3,4,5,6)
用卡诺图化简 F(A,B,C)=∑(2,3,6,7)
用卡诺图化简函数F(A,B,C)=∑(1,3,4,5,6,7)
用卡诺图化简逻辑函数 F(A,B,C,D)=∑m^4(0.2.8.10.11.12.13.14.15)
卡诺图化简F(A,B,C,D)=∑m(2,3,6,7,8,10,12,14)
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用卡诺图化简F(A、B、C、D)=∑m(2、5、7、8、10、12、13、15)RT
用卡诺图化简下列函数F(A,B,C)= ∑m(0,6)+∑mx(2,5)F(A,B,C,D)= ∑m(0,1,3,4,6,7,14,15+)∑mx(8,9,11,12)
用卡诺图化简F(A,B,C,D)=∑m(0,1,5,7,8,14,15)+∑d(3,9,12)答案给的是A'D+B'C'+ABC+AC'D'但是我觉得 卡诺图 的左下角那两个 约束项可以看成 就答案一共三项?
用卡诺图化简下列逻辑函数:F(A,B,C,D)=∑m(2,4,7,8)+∑d(10,11,12,13,14,15)
卡诺图化简F(A、B、C、D)=∑m(0、2、8、9、10、11、13、15)